X^2+6x-1332=0

Solution for X^2+6x-1332=0 equation:

X^2+6X-1332=0

a = 1; b = 6; c = -1332;
Δ = b2-4ac
Δ = 62-4·1·(-1332)
Δ = 5364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5364}=\sqrt{36*149}=\sqrt{36}*\sqrt{149}=6\sqrt{149}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6\sqrt{149}}{2*1}=\frac{-6-6\sqrt{149}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6\sqrt{149}}{2*1}=\frac{-6+6\sqrt{149}}{2}
$